-121x^2-486x-484=0

Solution for -121x^2-486x-484=0 equation:

-121x^2-486x-484=0

a = -121; b = -486; c = -484;
Δ = b2-4ac
Δ = -4862-4·(-121)·(-484)
Δ = 1940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1940}=\sqrt{4*485}=\sqrt{4}*\sqrt{485}=2\sqrt{485}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-486)-2\sqrt{485}}{2*-121}=\frac{486-2\sqrt{485}}{-242}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-486)+2\sqrt{485}}{2*-121}=\frac{486+2\sqrt{485}}{-242}
$